When you inherit a class using private keyword which members of base class are visible to the derived class?

When we inherit a class using private key word all functions in parent can be called by the child but not childs object in c++

see following example//Listing 12.3 Constructors and destructors called.
#include <iostream>
using namespace std;
enum BREED { GOLDEN, CAIRN, DANDIE, SHETLAND, DOBERMAN, LAB };
class Mammal
{
  public:
     // constructors
     Mammal();
    ~Mammal();
    //accessors
    int GetAge() const { return itsAge; }
    void SetAge(int age) { itsAge = age; }
    int GetWeight() const { return itsWeight; }
    void SetWeight(int weight) { itsWeight = weight; }
    //Other methods
    void Speak() const { cout << "Mammal sound!\n"; }
    void Sleep() const { cout << "shhh. I’m sleeping.\n"; }
  protected:
    int itsAge;
    int itsWeight;
};
class Dog : private Mammal
{
  public:
    // Constructors
    Dog();
    ~Dog();
    // Accessors
    BREED GetBreed() const { return itsBreed; }
    void SetBreed(BREED breed) { itsBreed = breed; }
    // Other methods
    void WagTail() const { cout << "Tail wagging...\n"; }
    void BegForFood() const { cout << "Begging for food...\n"; }
    void Speak2()const {Speak();} // Parent class object is accessible
  private:
    BREED itsBreed;
};
Mammal::Mammal():
itsAge(3),
itsWeight(5)
{
   std::cout << "Mammal constructor... " << endl;
}
Mammal::~Mammal()
{
   std::cout << "Mammal destructor... " << endl;
}
Dog::Dog():
itsBreed(GOLDEN)
{
   std::cout << "Dog constructor... " << endl;
}
Dog::~Dog()
{
   std::cout << "Dog destructor... " << endl;
}
int main()
{
   Dog Fido;
   Fido.Speak2();
   Fido.WagTail();
  // std::cout << "Fido is " << Fido.GetAge() << " years old" << endl; //this will give compilation error because GetAge is parents function can not be called by child object
   return 0;
}